time and work Model Questions & Answers, Practice Test for ssc chsl tier 1 2023

Answer: (c)

Man's two day's work = $2 × 1/{20}$ th work $1/{10}$ th work

Woman's two days's work

= 2 × $1/{30}$ th work = $1/{15}$ th work

Boy's two day's work = 2 × $1/{60}$ th work = $1/{30}$ th work

Now, let 2 men, 8 women and x boys can complete work in 2 days. Then ,

2 men's work +8 women's work + x boy's work =1

$2(1/{10}) + 8(1/{15}) + x(1/{30}) = 1$

⇒ x = $(1 - 1/5 - 8/{15}) × 30$⇒ x = 8 boys

Answer: (b)

Remaining distance = 3 km

and remaining time = $(1/3 × 45)min = 15 min = 1/4$ hr.

∴ Required speed = (3 × 4) km/h = 12 km/hr.

Answer: (a)

Number of man = ${30×6×9}/{25×8}$×10

= 81 men

Answer: (a)

50 men complete 0.4 work in 25 days.

Applying the work rule, $m_1 × d_1 × w_2 = m_2 × d_2 × w_1$

we have,

50 × 25 × 0.6 = $m_2$ × 25 × 0.4

or $m_2 = {50 × 25 × l 0.6}/{25 × 0.4}$ = 75 men

Number of additional men required = (75 – 50) = 25

Answer: (a)

Work done by A and B in 5 days = $(1/{10} + 1/{15}) × 5 = 5/6$

Work remaining = $1 - 5/6 = 1/6$

∴ C alone can do the work in 6 × 2 = 12 days

Ratio of their share work = $5/{10} : 5/{15} : 2/{12} = 3 : 2 : 1$

Share of wages = Rs 225, Rs 150, Rs 75.